ECE106 Lecture Notes - Lecture 10: Electric Field, Euclidean Vector, Bisection
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The direction of electric field cross-section density dense(large magnitude light(small magnitude. Figure 3. 6: lines of force of a dipole. Two equal but opposite charges are shown in fig. As it can be seen, the field lines seem to be symmetric near the charges. We should calculate the electric field due to a it to answer the aforementioned questions. rn r2 d g. We first consider the point o locating at a distance r along the perpendicular bisector of the dipole. 0 q (d/2)2 + r2 q (d/2)2 + r2 (3. 7) (3. 8) (3. 9) Note that the direction of the two fields are different. We need to perform the vector sum e 1 +e 2 to find the net field e .