ECE106 Lecture 27: ECE 106,University of Waterloo,(p27)
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Answer : to solve this consider the following symmetries: e in front of plane has same magnitude, e da of cylinder top and bottom, e points along z. 2s0 (4. 17) (4. 18) (4. 19) the factor 2 in the second equation is for the bottom and the top of the cylinder. Now let us see if you understand gauss"s law. It consists of a uniform charge on a sphere of radius a except for a small sphere b where it is 0. Calculate e at any point in the small sphere! When we add those two we can get the exact same charge distribution as in the problem.