ECE106 Lecture 38: ECE 106,University of Waterloo,(p38)

• School: University of Waterloo
• Department: Electrical and Computer Engineering
• Course: ECE106
• Professor: All

Document Summary

Let us assume that we have already assembled a sphere of radios r and now we want to add a thin shell with thickness of dr. From gauss law we know e due to qj outside of r is the same as if the charge qj is at the center. In presence of qj, how much work do we need to assemble (cid:466)dv1? dw1 = (cid:466)dv1. Area of spherical shell is 4(pi)r^2 needs to be fixed. Charge in shell =(cid:466) v olume of shell.