CET 3464 Lecture 4: 0gxoRdNynuYq

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Sogn 2 e two therefore, (a) initial slope is- 40 db/dec. The system type is equal to poles at origin & the radfs. 100 & 1000 frequencies open loop transfer function g(8) h(s) kas +100) corner 32 (s+1000) (6) initial slope = - 20 db/dec. It is type o system g(s)h(s) k (s +100) m(db) = 12 db finding k 20 as low frequencies, log | ko log to 12 | 12 0. 6 or 20 a. 6 k 100 gh = 4 ito. ols k = 400 s tloo (d) type g(3) his) = system k (sto. 5) (b +0. 05) (3+0:1) s terms be neglected. As low frequencies, for low frequences gh k xors look 0. 03 x01 20 log look 20 log look i look = 10 k=ool gh = 0. 1 (3+0. 5) (3+0. 0 (3+01 - 0. ) x0. 5 (1. +23) 0. 05x0. 1(1+203) (1 +10s gls) nis) = lo(1+28) (1+203) (1 + ios.