MATH 2300 Quiz: Quiz1SolutionsS10

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31 Jan 2019
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August 26, 2008: evaluate lim x 0+ xa ln x where a is any real number. a > 0 : lim x 0+ ln x x a xa ln x = lim x 0+ 1 a xa a x a = 0 : lim x 0+ xa ln x = lim x 0+ ln x = . 1 x a(cid:19) (cid:18) lim x 0+ ln x(cid:19) = ( ) ( ) = a < 0 : xa ln x = (cid:18) lim x 0+ lim x 0+

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