MATH 265 Midterm: MATH 265 Iowa State Midterm3 2011

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15 Feb 2019
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This test is closed book and closed notes. For full credit show all of your work (legibly!). Each problem is worth 10 points (a total of 50 points): rewrite. 0 f (x, y) dy dx +z 1. 0 f (x, y) dy dx +z 2. 1 f (x, y) dy dx as a single integral of the form. If we sketch the region that the three integrals corresponds to, we see that we are bounded by the lines y = 0, y = 3, y = 3 + 3x and y = x2 1. The last two we can rewrite as x = (1/3)y 1 and x = y + 1 (we take the positive square root because we want the right hand side, i. e. , positive x-values). It is now easy to set up the desired integral and we have. Z 3 (1/3)y 1 f (x, y) dx dy.