030.102 Midterm: Exam 1 Solutions Dagdigian Spring 2010
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Calculators allowed, but do not use programmable features. One sheet of paper with notes may be brought into the exam. !e = !e (rt/nf) lnq = !e (0. 0592 v/n) logq at 25 c. !e = (rt/nf) lnk = (0. 0592 v/n) logk c = c0 e kt ph = log[h3o+] 1/c = 1/c0 + 2kt: galvanic cells. The following reduction potentials are available: jhed id__________________ T(k) = t(c) + 273 k = ae ea/rt (aq) + 3 e " au(s) + 4 cl (aq) !e = e (cathode) e (anode) = +1. 062 ( 0. 762) Zn2+(aq) + 2 e " zn(s) (a) consider an electrochemical cell containing a zinc anode immersed a solution containing. The molar mass of au is 197. 0 g mol 1. Q = i t = (0. 75 c/s)(150 min)(60 sec/min) = 6750 c. Mass of gold plated = _____4. 59__________ g moles electrons = 6750 / 96485 = 0. 0700.
