CHEM 1201 : Kolniak Spring 2013 Exam 3 Blank
CHEM 1201 Sec 01 Spring 2013
EXAM 3 Chap 7 and 8 Dr. Kolniak
FORM 1
If you have a question about the content of any of the problems or the answers provided,
raise your hand. Make sure that every problem has an answer bubbled in on the
scantron and DOUBLE check your answers on the scantron.
Select the best answer (6.25 pts each).
1. What is the formal charge on the nitrogen atom in the lewis structure below?
a. –2
b. –1
c. 0
d. +1
e. +2
2. Which of the following oxides would be the most basic when added to water?
a. K2O
b. SO3
c. CaO
d. FeO
e. ClO2
3. Select the correct answer(s). What is wrong with this picture …. ClO3- molecule. Hint:
redraw.
I. To few bonding pairs on the Cl atom.
II. Too few electron pairs were used
III. An octet violation on an Cl atom
IV. Too many electron pairs were used
a. I only
b. II only
c. I and II only
d. II and III only
e. I, II and III only
4. What volume (ml) of 0.8 M H3PO4 requires 35 ml of an 0.5 M NaOH solution to reach
the equivalence point?
3 NaOH (aq) + H3PO4 (aq) Na3PO4 (aq) + 3 H2O(l)
a. 21.88 ml
b. 5.42 ml
c. 65.63 ml
d. 35.00 ml
e. 7.29 ml
5. Based on the trends of the periodic table, arrange the following atoms in order of
INCREASING Ionization Energy: Be, N, Ca, Ne, Rb
a.
Rb
<
Ca
<
Be
<
N
<
Ne
b.
Rb
<
Be
<
Ca
<
N
<
Ne
c.
Ne
<
N
<
Be
<
Ca
<
Rb
d.
Rb
<
Ca
<
Be
<
Ne
<
N
e.
Ne
<
Rb
<
Ca
<
Be
<
N
6. Place the following in order of increasing stability for CSO?
Electronegativities: C= 2.5, S = 2.4, O = 3.5
a. I< II<III
b. II<I<III
c. III<II<I
d. I<III<II
e. II<III<I
7. Which one of the following elements has the MOST metallic character?
a. Bi
b. Hg
c. Au
d. Pt
e. W
Document Summary
Exam 3 chap 7 and 8 dr. kolniak. If you have a question about the content of any of the problems or the answers provided, raise your hand. Make sure that every problem has an answer bubbled in on the scantron and double check your answers on the scantron. To few bonding pairs on the cl atom. 3 naoh (aq) + h3po4 (aq) na3po4 (aq) + 3 h2o(l: 21. 88 ml, 5. 42 ml, 65. 63 ml, 35. 00 ml, 7. 29 ml, based on the trends of the periodic table, arrange the following atoms in order of. Increasing ionization energy: be, n, ca, ne, rb. Electronegativities: f: 4. 0 o: 3. 5 h: 2. 2 c: 2. 5. Ii and iii only: all, place the following ionic compound in order of increasing lattice energy: Cacl2 < sccl3 < nacl < nicl4: nicl4 < cacl2 < sccl3 < nacl.
