MATH 0120 Midterm: Math 0120 Exam 2 (0120) Solutions spring 2013-298

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31 Jan 2019
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S o l u t i o n s: (a) [10 points] find f (2) if f (x) = e. Hence, f (x) = 0 for any x and, in particular, f (2) = 0. (b) [10 points] find f (1) if f (x) = ex ln(x2). Product rule: f (x) = 2ex ln x + 2ex. Then f (1) = 2e 0 + 2e 1 = 2e: [15 points] for the function f (x) = x3. 9x2 + 24x make the sign diagram that contains both the rst and second derivatives and sketch its graph. 6x + 8) = 3(x 2)(x 4). Concavity: f (x) = 6x 18 = 6(x 3). Ip is x = 3. f (x) < 0 when x < 3, f (x) > 0 when x > 3. Using this information make the sign diagram and sketch the graph of the function.

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