MATH 112 Final: MATH112 Final Exam 2012 Winter Answer

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11 Oct 2018
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1. (a) t = 36. 25 (b) t = 2, 11 (c) concave up (d) g(t) = 0. 048t2 0. 48t + 1. 422 (e) a is smaller. F; x. t (b) approximately 53. 55 feet (c) any one-minute interval containing t = 8 is correct (d) 4 feet per minute (e) 192 feet. 2 q 1/2 tet + et(cid:105) (b) h(cid:48)(t) = (ln t)3(cid:104) (cid:18) 7u 6 (cid:19) 3(cid:20) (3u + 4)(7) (7u 6)(3) 10s2 + 3t9 27t8 (d) ms(s, t) = 2st6 + Mt(s, t) = s2(6t5) + (cid:18) 1 (cid:19) t (c) 3u + 4 (3u + 4)2 (cid:21) (a) 13. 25 (b) 3ex + 4.

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