MATH 125 Midterm: MATH 125 UW 125 Sp12 Sol1

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31 Jan 2019
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MATH 125 Full Course Notes
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Math 125, section a, spring 2012, solutions to midterm i: evaluate the following integrals. (a) z 3. 0 t2 + t 1 t + 2 dt. Do the substitution u = t + 2 to get. Z 5 (b) z arctan x x2 + 1 (u 2)2 + (u 2) 1 u du =z 5. Do the substituion u = arctan x to get u2. 7x2 + ex sin x dx = + ex + cos x(cid:12)(cid:12)(cid:12) g(x) =z x2+1 x. 0 ln(cid:0)t3 + 1(cid:1) dt (a) compute g (2). By the fudamental theorem of calculus and the chain rule g (x) = ln(cid:16)(cid:0)x2 + 1(cid:1)3. + 1(cid:17) (2x) ln(cid:0)x3 + 1(cid:1) so (b) approximate g(2) with n = 6 and using left points. Is your approximations more than or less g (2) = ln(cid:16)(cid:0)22 + 1(cid:1)3. L6 ="ln(cid:0)23 + 1(cid:1) + ln (cid:18) 5. 2 g(2) =z 5 ln(cid:0)t3 + 1(cid:1) dt.

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