MATH 126 Final: MATH 126 UW Final Exam Winter 2016 Solutions

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31 Jan 2019
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Final exam answers (a) = cos 1(cid:18) (b) (5, 4, 6) , 0(cid:19) (b) (cid:18) (a) y = 3 3 x (b) area=2 + 0 p1 + y2 dx dy = (a) r(t) =(cid:10)2 cos t + 3 sin t, cos t 6 sin t, 40 cos t + 40(cid:11) (b) an = 45. 4( 5)k(cid:21) xk+1 (2 2 1) k + 1 (a) 2 x3 (c) t3(x) = 9 (a) t2(x) = (1 )(x 1) + ( 2+2) (b) on the interval (cid:20) 1. |f (x)| = | 3 cos( x) + 3 sin( x) + 6(2 x) 4| 2 3 + 96 162. Then error=|t2(x) f (x)| 162 (c) using m from part (b), 6 |x 1|3 = 27|x 1|3 0. 001 if |x 1| . I = [0. 967, 1. 033] (other answers are possible. )

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