ECN 102 Study Guide - Final Guide: Heteroscedasticity, Multicollinearity, Dependent And Independent Variables

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9 Jan 2019
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= (cid:22)x (cid:6) t:025;n(cid:0)1s=pn = 14022:5 (cid:6) t:025;199 (cid:2) 5217:457=p200 = 14022:5 (cid:6) 1:9720 (cid:2) 368:93. = 14022:5 (cid:6) 727:53 = (13295, 14750). (b) h0 : (cid:22) (cid:20) 13000 versus ha : (cid:22) > 13000 where claim is the alternative hypothesis: t = ((cid:22)x (cid:0) (cid:22)0)=(s=pn) = (14022:5 (cid:0) 13000)=(5217:457=p200) = 1022:5=368:93 = 2:772: Reject h0 at level :05 if t > t:05;199 = 1:6525. Conclude that (at sig. level 0. 05) population mean sales exceed 13,000 units. (c) percentiles, median, skewness, kurtosis (also will allow smallest values and largest values). 2. (a) a 95% con(cid:12)dence interval for (cid:12)sales is (42:23; 52:84) from regression output. (b) 99% con(cid:12)dence interval for population slope parameter. = 47:537 (cid:6) 6:999 = (40:54, 54:54). (c) h0 : (cid:12)2 = 50 against ha : (cid:12)2 6= 50. t = (b2 (cid:0) 50)=sb2 = (47:537 (cid:0) 50)=2:691 = (cid:0):915. jtj = :915 < t:005;198 = 2:691.