PHY 2053 Midterm: Sum13Exam1Solutions

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turquoisegnu128

31 Jan 2019

School

University of Florida

Department

Physics

Course

PHY 2053

Professor

All

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Document Summary

The only combination that gives f"/f = 2 is doubling m1: the speed of light is. 10 furlongs fortnight: the distance traveled for the entire trip is v xav x t v xav t x. The distance covered during the first part is x t v xav t v xav x. The distance for the second part is x. The average velocity for the second part is v xav x t. 60 min hr1 mph: for the first 10 s, the distance is 120 m. this gives, t v ix x x. 14 m s v ix s)6( a x. 14 m s m s v ix s)5( a x v ix s)6( a x. 12 m s a x v ix s)5( a x. 14 m s v ix s)6( a x v ix v ix m s. 0. 2 v ix m s: the acceleration is t.

Related Questions

Figure 1 illustrates a Keplerian orbit, with Cartesiancoordinates (x,y) and polar coordinates (r,Ï).

Parametric equations for a general Keplerian orbit are r(Ï) = a(1 â e cosÏ)

t(Ï) = *(T)/2Ï+ ( Ïâ e sinÏ)

tan(Ï/2) = *(1+e)/(1âe)+1/2 tan(Ï/2)

Here Ï is an independent variable. The solution is periodic in Ïwith period âÏ = 2Ï. Also, a, e, T are constants that determine theparameters of the orbit.

Figure 2 shows the relation between Ï and the spatialcoordinates. In the figure, the coordinates (Î¾,Î·) are defined by Î¾= x + ae and Î· = y a /b,

withb=a*1âe2 ]1/2.

(A) What kind of curve is the orbit?

(D) Determine Î¾(Ï) and Î·(Ï).

(E) Express r as a function Ï .

(F) The angular momentum is L = m r2dÏ/dt. Determine L in termsof {a,e,T} Hence verify that L is a constant of the motion.

(G) The energy isE = [1/2] m ( dr/dt )2+ [1/2] m r2(dÏ/dt)2â GMm/r.Determine E in terms of {a,e,T}.

(H) E must be a constant of the motion. Hence determine T and Efrom the equation that you obtained in (F).

(I) Write T in terms of the spatial orbit parameters and theforce constant GM.

(J) Now express L and E in terms of a, e, GM.

(K) In Figure 1, determine the coordinates of the points P, A,and R

(L) In Figure 1, determine the time t at the point R.

Zero Net Force A spaceship is on a straight-line path between Earthand its moon. At what distance from Earth is the net gravitationalforce (due to the Earth and Moon only) on the spaceship zero?
(answer)km

Section 14.3 Gravitation and Superposition

I figure that I would have to use Earth's mass = 5.9E+24kg, andGravitational Force = 6.67E-11N*m^2/kg^2
Fnet = (G*m1*m2)/r^2

PHY 2053 Midterm: Sum13Exam1Solutions

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Physics: Principles with Applications

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