IE 4453 Chapter : HW4
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For first sample: probability of defects, probability of acceptance, probability of rejection: The normal single sampling plan is n=125, acceptance number=3, rejection number=4. To find the tightened single sampling plan from mil std 105e: aql = 1, inspection level = general ii, n = 3000, sample size code for n=3000 = k (table 15. 4, sample size n=125, acceptance number=2, rejection number=3. The tightened single sampling plan is n=125, acceptance number=2, rejection number=3. To find the reduced single sampling plan from mil std 105e: aql = 1, inspection level = general ii, n = 3000, sample size code for n=3000 = k (table 15. 4, sample size n=50, acceptance number=1, rejection number=4. The reduced single sampling plan is n=50, acceptance number=1, rejection number=4: find dodge romig sampling plan. Given: n=2000, ltpd=1%, average process fallout p=0. 25% (table 15. 9) n=490, c=2, aoql=0. 2% Oc curve for single sampling plan n=490, c=2: probability of acceptance vs. fraction defective (p)
