ECOR 2606 Lecture Notes - The Roots, Semicolon, Nspace
Document Summary
Problem: a room is 4m longer than it is wide. Let x be the width of the room. Then the area of the room is: x(x + 4) = x2 + 4x. Equating this to the given area gives: x2 + 4x = 20. Rearranging gives: x2 + 4x 20 = 0. Root finding problems: general form: find x such that f(x) = 0, the values of x for which f(x) = 0 are the roots of f(x) For our problem f(x) happens to be a quadratic. The roots can be found using the quadratic formula. xf. One is obtained by using + in the formula and the other by using -. If the quantity under the square root is zero the roots are equal. If this quantity is negative the roots are complex numbers. Use the right arrow to move from unknowns? to degree? . Enter 2 (a quadratic is a second degree polynomial)