MAAE 2202 Lecture 6: Solids (I) Notes - Chapter 6

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Chapter 6 symmetric bending of beams (ii) deflection. Beams deform under bending loads, resulting in deflection and slope of the beams. Consider the deformation of a cantilever beam subjected to a concentrated load at the free end. v is the vertical deflection and is the rotation or slope of the beam. = rs dv= dx dv tan ( is small. ) dx (6. 1) (6. 2) Curvature dx because (6. 3) (6. 4) cos when is small. 1 (6. 5) x x dv dx dv dx dv dx x dv dx x x x. Negative sign (-) here means that deflection v is positive when moment m is negative. dv= dx will be obtained by integration of eqn (6. 8). v will be obtained by integration of dv dx. 6. 2. 1 cantilever beam subjected to a point load. 6. 2. 2 cantilever beam subjected to a uniformly-distributed load. 6. 2. 3 simply supported beam under a uniformly-distributed load. 6. 2. 4 simply supported beam under a concentrated load bap .

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