ENGG 202 Lecture Notes - Lecture 1: Cross Product, Unit Vector, Contact Force
26 Jan 2015
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Review equilibrium: the block has a weight of 100 n which acts at the centre a. The surface is frictionless so the contact force is normal to the inclined surface. Solution strategy: draw the fbd of the block. There are 3 forces acting on the fbd, the weight (vertical), normal force perp to the surface, and force p. easiest would be to use a rotated set of axis (parallel and perp to slope) Find the components of all the forces, write the eqns of equil and solve. A: determine the force acting along each strut (ab, Ac, and ad) necessary to hold the 200 n plant pot in equilibrium. Points b and d lie in the x-z plane. Ans: fac = 250 n (away from a), fba = 115 n (toward a), fda = 150 n (toward a) Solution strategy: draw the fbd of point a. it has 1 known (the weight) and 3 unknown forces (ad, ac,
