CHEM 1040 Lecture Notes - Lecture 24: Sodium Acetate, Conjugate Acid, Chemical Equation

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Chem 1040- lecture 24- k values , ph and buffers. You need to know two things for aqueous buffer systems: Did a chemical reaction occur: determines from net ionic equation. Is the process complete as written: determined from k value. If the reaction involves a weak acid/base, a reaction occurs. If the reaction involves a strong acid/base, the compounds only dissociated. K+, na+, li+, ca2+, ba2+, sr2+ from oh- We want the k value for the reaction going from left to right. The k value is determined from the species that is mixing with the water. When water is on the left, a dissociation or normal process occurs: the k value is used directly. Ex: show the net ionic equations and k expressions for the following: sodium acetate in water. Kch3coo- = kw / kch3cooh: acetic acid mixed with sodium hydroxide. Ch3cooh + oh- --> h2o + c h3coo- This is the reciprocal of the above reaction, so:

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