PHYS 1070 Lecture Notes - Lecture 11: Electrical Network, Electrostatics, Circuit Diagram

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cyanrat665

26 Sep 2012

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Electric force from a charge q-2, felt by another charge q-1. Relationship between electric forces felt by q-1 in electric field generated by q-2. Electric field lnes can be drawn to give us a vector map of the forces & fields that will interact with our positive test charge. & we realize that the vector nature of f and e need to be taken into account when. Solving for the forces & fields at specific locations. Work is required to move a charge within an e-field. Positive work required to move it against e field time. Negative work required to move it with e field time. This work is equal to the change in the stored pe of the charge. W = k q1 q2 / k r -work done moving a charge q2 in a field generated by q1. V = k q / k r -electric potential generated by a charge q.

Related Questions

In an electric field, energy per unit positive charge is:

voltage
current
frequency
resistance

champagnepanda184

1.Two uncharged, conducting spheres, A and B, are held at rest oninsulating stands and are in contact. A positively charged rod isbrought near sphere A. While the rod is in place, the two spheresare separated. How will the spheres be charged, if at all, afterthey are separated?
Sphere A Sphere B
(a) positive positive
(b) positive negative
(c) negative positive
(d) negative negative
(e) zero zero

2. A charged conductor is brought near an uncharged insulator.Which one of the following statements is true?
(a) Both objects will repel each other.
(b) Both objects will attract each other.
(c) Neither object exerts an electrical force on the other.
(d) The objects will repel each other only if the conductor has anegative charge.
(e) The objects will attract each other only if the conductor has apositive charge.

3. An electron is moved from point A, where the electric potentialis VA = â240 V, to point B, where the electric potential is VB =â360 V. What is the change in the electric
potential energy?
(a) 1.92Ã10â17 J (b) 2.04Ã10â17 J (c) 5.75Ã10â17 J (d) 8.98Ã10â17 J(e) 1.05Ã10â16 J

4. A -2q charge is located a distance d to the right of a +4qcharge, along the x
axis. At which point (or points) along the axis does the electricfield go to zero? To
solve this problem, consider an observer at point P, which is anarbitrary distance x from the +4q charge. Find the value (orvalues) for x (in terms of the separation distance d) where thetotal electric field vanishes.
(a) The electric field is never zero in the vicinity of thesecharges.
(b) The electric field is zero at x = -0.328d.
(c) The electric field is zero at x = +4.22d.
(d) The electric field is zero at both x = -2.26d and x =+2.26d.
(e) The electric field is zero at x = +3.41d.

5. point A is a distance L away from a point charge Q. Point B is adistance 4L away from Q. What is the ratio of the electrostaticpotential at B to that at A, i.e., what is VB/VA?
(a) 1/16
(b) 1/9
(c) 1/4
(d) 1/3
(e) can not be determined without specifying Q and L

6. Which one of the following statements best explains why it ispossible to define an electric potential
in a region of space that contains an electric field?
(a) Work must be done to bring two positive charges closertogether.
(b) Like charges repel one another and unlike charges attract oneanother.
(c) A positive charge will gain kinetic energy as it approaches anegative charge.
(d) The work required to bring two charges together is independentof the path taken.
(e) A negative charge will gain kinetic energy as it moves awayfrom another negative charge.

A copper wire has radius r = 0.0245cm, is 3.05 m long, hasresistivity
Ï = 1.72 Â· 10â8 Î© m, andcarries a current of 0.360 A.The wire has density of charge carriers of 8.50 Â· 10^28 electrons/m^3. (When enteringunits, use ohm for Î©.)

(a) What is the resistance, R, of the wire?

(b) What is the electric potential difference,ÎV, across the wire?

PHYS 1070 Lecture Notes - Lecture 11: Electrical Network, Electrostatics, Circuit Diagram

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