PHYS 1300 Lecture Notes - Lecture 11: Circular Motion
Document Summary
Newton"s first law: a boy"s soapbox derby car is pushed with a broom handle. The total mass of the car and the boy combined is 36. 7 kg and a force of 72. 7 n is applied along the direction of the broom handle making an angle of 69. 30 with the vertical. There"s a frictional force with a magnitude of 12. 7 on the car. If the boy starts from rest, how far will the car travel in 1. 50s. | a| = 72. 7 n sin69. 30 = fax / | a| Fax = | a|sin69. 30 ax = (| a|sin69. 30 ff) / m ax = (fax ff) / m ax = (72. 7sin69. 30 12. 7) / 36. 7 kg ax = 1. 507 m/s2: = m . Fx = max ax = ? m/s2 x0 = 0 x = 0 v0 = 0 ax = 1. 507 m/s2 t = 1. 50 s x = x0 + v0t + at2 x = 170 m.