PLAN 350 Lecture 17: PLAN 350 – Lecture 17 – February 11.pdf
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Plan 350 lecture 17 february 11, 2015. We have an array of 151+ census tracts, ordered by average household size (ahs)- 1. For all these subareas, dt/nt > number of households/nt, but for the residential area we assume that dt/nt = (ahs)- 1. Estimate of downtown: arbitrarily assign ratios (in this case, we"ll start with 12) A (downtown) zz (most residential) our example = (12- 0. 3)/(149) = 0. 08. Check the associated daytime population: try tract e from example: dt/nt = 11. 68, dte = 11. 68nte. We now have an estimate of this tract"s daytime population. Grand total dt nt ( 5%) We have estimated daytime population from nighttime population and diurnal ratio. Is that equal (or close) to the grand total for nighttime population? typically, the answer will be no. Downtown diurnal estimate and increments accordingly. 4. iterate (try again) until you are within 5- 10% of the grand total.
