ACTSC221 Lecture 1: chap6solstudent_notes.pdf

75 views17 pages

Document Summary

P = 22. 50a40|. 04 + 500(1. 04) 40 or p = 500 + (22. 50 20)a40|. 04 = . 48. P = 65a30|i + 2000(1 + i) 30 where i = (1 + 0. 07 or p = 2000 + (65 2000i)a30|i = . 17. P = 45a36|. 06 + 1100(1. 06) 36 or p = 1100 + (45 66)a36|. 06 = . 96. P = 525a30|i + 10 250(1 + i) 30 where i = (1 + 0. 07 or p = 10 250 + (525 10 250i)a30|i = 191. 71. P = 30 000a40|i + 1 050 000(1 + i) 40 where i = (1 + 0. 055 or p = 1 050 000 + (30 000 1 050 000i)a40|i = 068 973. 16. 12 )6 1: p (per ) = 5a24|. 045 + 100(1. 045) 24 or p = 100 + (5 4. 50)a24|. 045 = . 25. Part b: p = c + (f r ci)an|i. If f r = ci then p = c. P1 = x r a20|. 05 + 1. 05x(1. 05) 20.

Get access

Grade+20% off
$8 USD/m$10 USD/m
Billed $96 USD annually
Grade+
Homework Help
Study Guides
Textbook Solutions
Class Notes
Textbook Notes
Booster Class
40 Verified Answers
Class+
$8 USD/m
Billed $96 USD annually
Class+
Homework Help
Study Guides
Textbook Solutions
Class Notes
Textbook Notes
Booster Class
30 Verified Answers

Related Documents