MATH106 Lecture 17: 2.2 - Gauss-Jordan Elimination

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By doing drastically simplify the back substitution process row operations. Rz rz it"t itas we quickly get 1 1 1. The matrix is in a very type of ref called reducedrowechelonform. A matrix is said to be in reduced row echelon if in. Ref leading entries it all in any column with a leading 1 entries are o are. 3 z fig og 9,34g is in rref but. O o o are not they fail z and 3 respectively to a a. We can always put a matrix writing it in ref the leading 1 s from right to left into rref by first and then eliminating the entries above. L l in rref and find the general solution. Go f ii g re 214 fo o o. Since xe is not the solution is free. Kref it"s unique i matrix has one and only one rref. This is not the case for ref leading t.

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