MATH 105 Lecture 34: MATH 105 Lecture 34

• School: UBC
• Department: Mathematics
• Course: MATH 105
• Professor: LIU, KEQIN

Document Summary

We then approximate y 1 and construct a line through the point (t 1 , y 1 ) that has a slope f(t 1 , y 1 ). This gives: y = y 1 + f(t 1 ,y 1 ) (t - t 1 ) This gives: y 2 = y 1 + f(t 1 ,y 1 ) (t 2 - t 1 ) y 3 = y 2 + f(t 2 ,y 2 ) (t 3 - t 2 ) y 4 = y 3 + f(t 3 , y 3 ) (t 4 - t 3 ) In general, if we have tn, the approximate solution to this point yn, and we want to find the approximation at tn+1 we do the following y n+1 = y n + f(t n ,y n ) (t n+1 - t n )