CHM120H5 Lecture Notes - Lecture 38: Orbital Hybridisation, Unpaired Electron, Pi Bond
Document Summary
Sp2 carbon atom with one unhybridized p orbital. Sp2 carbon with one unhybridized p orbital sp carbon atom with two unhybridized p orbitals. This carbon atoms is rotated to 90 degrees so as to make both p orbitals in the same direction to form the pi bond. H atoms on the end carbon atoms are in different planes. Molecules having central atom in sp3 but having non- tetrahedral shape. # n undergoes sp3 hybridization to form four equivalent orbitals. # three of the orbitals will hold the unpaired electrons and bond with h atoms. # there will be a pair of electrons in the fourth orbital. # nh3 molecule will have a pyramidal shape. # the lone pair is more concentrated on n atom than the bond pair which is in the n-h bond. # the lone pair-bond pair repulsion is greater than the bond pair-bond pair repulsion. # the bond angle is reduced to 1070.
