I think B was the best answer..
Because an indexed set {v1,...,vp} of teo or more vectors, with not being v1 zero vector, is linearly independent if and only if some vj is not a linear combination of the preceding vectors, v1,...,v(j-1)
but its answer is D
plz explain the answer using the <Linearly Independent sets Theorem>
(1 point) Assume u4 is not a linear combination of Select the best statement. A. { ul , u2, u3, u4 } is never a linearly independent set of vectors. B. {ul , u2, u3, u4} is a linearly independent set of vectors unless one of (ul , u2, u3 } is the zero vector. Ð Ñ. {u1, u2, u3, u4} could be a linearly independent or linearly dependent set of vectors depending on the vector space chosen. D. {u1, u2, u3, u4} could be a linearly independent or linearly dependent set of vectors depending on the vectors chosen OE. [u, u2, uz, u4) is always a linearly independent set of vectors. F. none of the above