1002 Lecture Notes - Material Conditional, Atomic Sentence

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bronzemoose8

5 Feb 2013

School

Buffalo State College

Department

Philosophy

Course

1002

Professor

James Hildebrand

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Document Summary

A completed open branch proves that p cannot be t-f false. This is because it proves that there is at least one tva on which p is true: a completed open branch proves that p and q are not t-f equivalent. This is because there are 8 different possible truth value assignments to a sentence containing 3 atomic components and from the two open branches mentioned there are only 4 that can be recovered. Any tva on which a and b are either both true or both false cannot be recovered. However, because there are other tva"s that can be recovered we know the sentence cannot be t-f false. In particular, we know that it must be true on any tva on which a and b have different truth values: a. The tree for the unit set, {a v b}, has all open branches, but the sentence, A v b, is not a t-f true sentence.

Related Questions

Which of the statements regarding this situation are true? Selectall that apply.

1-When one charged sphere is placed inside another the net electricfield outside the larger sphere is always larger than the field dueto the larger sphere alone.

2-If there is a positive point charge present at the center, thefield in all regions is either zero or directed away from thecenter.

3-When one charged sphere is placed inside another the net electricfield outside the larger sphere is always non-zero.

4-It is possible to have no electric field inside the outer sphereand a non-zero electric field outside the outer sphere.

5-If the outer sphere is present the electric field between itsinner radius and its outer radius (inside its solid wall, in otherwords) is always zero.

6-It is not possible to have a non-zero electric field inside theinner sphere and outside the outer sphere, but no electric fieldbetween the inner and outer spheres.

7-For a conducting sphere with a net charge Q, the electric fieldinside the sphere is zero and the electric field outside the sphereis the same as the field from a point charge of charge Q placed atthe center of the sphere.

8-As you move steadily out from the origin in this simulation theelectric field changes smoothly. The field can never jump suddenlyfrom one value to another.

9-If the outer sphere is present the way charge is distributed onthe outer sphere depends only on its charge, and not on the chargeof the point charge and the inner sphere.

A metal cannonball of mass m rests next to a tree at the very edge of a cliff 36.0 m above the surface of the ocean. In an effort to knock the cannonball off the cliff, some children tie one end of a rope around a stone of mass 80.0 kg and the other end to a tree limb just above the cannonball. They tighten the rope so that the stone just clears the ground and hangs next to the cannonball. The children manage to swing the stone back until it is held at rest 1.80 m above the ground. The children release the stone, which then swings down and makes a head-on, elastic collision with the cannonball, projecting it horizontally off the cliff. The cannonball lands in the ocean a horizontal distance R away from its initial position.

(a) Find the horizontal component R of the cannonball’s displacement as it depends on m.
(b) What is the maximum possible value for R, and
(c) to what value of m does it correspond?
(d) For the stone–cannonball–Earth system, is mechanical energy conserved throughout the process? Is this principle sufficient to solve the entire problem? Explain.
(e) What if? Show that R does not depend on the value of the gravitational acceleration. Is this result remarkable? State how one might make sense of it.

crimsonmule224

(There is a arrow symbol over the r in this problem denotingthat it is a vector) Suppose there is a charge distribution p(r,t),which has spherical symmetry at anytime.In other words, p(r,t) onlydepends on the magnitude or r and t, but not on the angle of r. Thevelocity distribution of charges is spherically symmetrical, i.ev(r,t) is along the radial direction and only depends on theabsolute value of r and t.

1) By using symmetry analysis, determine the distribution of B(r)(Both B and r have arrow symbols above them denoting they arevectors) Hint: you also need to know the fact that no magneticmonopoles exist.

2) What's the displacement current distributionJd=(1/(4p))(dE/(dt)) (Note that there is an arrow above J and E inthe previous equation noting that these are vectors and d is asubscript) Whats the relationship between Jd (the j has an arrowover it indicating it is a vector and d is a subscript) and theactual current density J (with an arrow over it indicating it is avector J)? Explain why your result in part 1) is correct eventthough it looks counter intuitive.

1002 Lecture Notes - Material Conditional, Atomic Sentence

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