CHEM 1021 Lecture Notes - Lecture 20: Horse Length, Specific Volume, Nonmetal

23 views2 pages
8 Oct 2016
Department
Course
Professor

Document Summary

Mass solution = mass solute + mass solvent. Use the same mass units for all masses. Mass percent has no units or in grams. Mass percent naoh = 8. 00 g / 58. 00 g x 100 = 13. 8% naoh. 1 g of solute in 100 g of solution. Mass percent is commonly used in commercial solutions. Physiological saline solutions used in intravenous injections have a concentration of 0. 90% sodium chloride by mas. How many grams of sodium chloride are needed to prepare 500. g of solution. Second wat to try: conversion factor - dimensional analysis approach (500. g solution)(0. 0090 g nacl/1 g solution) = 4. 5 g nacl. 1. 00 mol naoh | {(1 l solution)/(0. 2 mol naoh)} = 5 l. It is estimated that the concentration of gold in sea water is 2. 03 x 10^-11 (mol/l). | 1 l | 1 mol au | The amount of solvent changes (more is added) The amount of solute is staying the same.

Get access

Grade+20% off
$8 USD/m$10 USD/m
Billed $96 USD annually
Grade+
Homework Help
Study Guides
Textbook Solutions
Class Notes
Textbook Notes
Booster Class
40 Verified Answers
Class+
$8 USD/m
Billed $96 USD annually
Class+
Homework Help
Study Guides
Textbook Solutions
Class Notes
Textbook Notes
Booster Class
30 Verified Answers

Related textbook solutions

Related Documents

Related Questions