Engineering and Applied Sciences Applied Physics 216 Lecture 2: Lecture 2

• School: Harvard University
• Department: Engineering and Applied Sciences
• Course: Engineering and Applied Sciences Applied Physics 216
• Professor: Jene Golovchenko

Document Summary

Ap 216 lecture 2 the gauge fields a. Review and (cid:73) (cid:112) identically satisfied if e. In lecture 1 we showed that (cid:146)(cid:112) (cid:112) and b (cid:71) (cid:71) , (cid:307) are. (cid:112: e (cid:112, b. + (cid:119) b (cid:112) (cid:99) (cid:119) t = 0 would be (cid:112) were determined from gauge fields a. + (cid:733) 0 (cid:80)0 (cid:119) e (cid:112) (cid:112) (cid:99) (cid:119) t when a. 2 (cid:146) (cid:14) (cid:77) (cid:71) (cid:146) (cid:152) (cid:11) (cid:119) (cid:119) t (cid:71) 2 (cid:119) (cid:119) t (cid:32) (cid:16) (cid:71) (cid:85) (cid:733) (cid:71) (cid:167) (cid:168) (cid:169) 0j (cid:32) (cid:16) (cid:183) (cid:119) (cid:77) (cid:184) (cid:119) (cid:185) t. Finally discussed gauge transformations derived from scalar function f (cid:71) A f (cid:111) (cid:16) (cid:77) (cid:77) (cid:119) (cid:119) f t. Pick f so (cid:71) (cid:146) (cid:152) (cid:14) (cid:71) 0 (cid:77) (cid:85) (cid:139) t (cid:15) (cid:32) (cid:16) They are coupled by continuity equation and lorentz gauge condition. (cid:112) 0 (cid:71) g x t (cid:32) (cid:119) (cid:77) (cid:119) t (cid:71)