CHEM 127 Lecture Notes - Lecture 1: Sodium Methoxide, Sodium Ethoxide, Sodium Hydroxide

49 views4 pages
26 May 2018
Course
Professor
Chemistry 8.1-8.11
8.1
Elimination reaction: involves loss of elements from the starting material to form a new Pi
bond in the product
- Alkyl halides undergo elimination reactions with Bronsted-Lowry bases. The element
HX are lost and an alkene is formed.
Dehydrohalogenation: removal of the elements of HX, one of the most common methods to
introduce a Pi bond and prepare and alkene.
- It is an example of Beta elimination because it involves loss of elements from two
adjacent atoms: the sigma carbon bonded to the leaving group X, and the Beta
carbon adjacent to it.
- Common bases used in Dehydrohalogenation: Sodium hydroxide, potassium hydroxide,
sodium methoxide, sodium ethoxide, potassium tert-butoxide
- To draw any product of dehydrohalogenation:
1) Find the sigma carbon-the sp3 hybridized carbon bonded to the leaving group
2) Identify all Beta carbons with H atoms
3) Remove the elements of H and X from the sigma and beta carbons and form a
Pi bond
8.2
- The sigma bond, formed by end-on overlap of the two sp2 hybrid orbitals, lies in the plane of
the molecule
- The Pi bond, formed by side-by-side overlap of two 2p orbitals, lies perpendicular to the plane
of the molecule. The pi bond is formed during elimination
Monosubstitued alkene: has one carbon atom bonded to the carbons of the double bond.
Disubstituted alkene: Has two carbon atoms bonded to the carbons of the double bond and so
forth
- The cis isomer has two groups on the same side of the double bond
- The trans isomer has two groups on opposite sides of the double bond
- Trans alkenes are generally more stable than cis alkenes
Diastereomers: Stereomers, but not mirror images of each other
Whenever the two groups on each end of a carbon-carbon double bond are different from
each other, the two diastereomers are possible
- The stability of alkenes increases as the number of R groups bonded to the double bond carbons
increases
- R groups increase the stability of an alkene because R groups are sp3 hybridized,
whereas the carbon atoms of the double bond are sp2 hybridized.
- sp2 hybridized carbon atoms are more able to accept electron density and sp3 hybridized
carbon atoms are more able to donate electron density
- Increasing the number of electron-donating R groups on a carbon atom able to accept electron
density makes the alkene more stable
- Trans alkenes are more stable than cis alkenes cause they have fewer steric interactions
- Increasing alkyl substitution stabilizes an alkene by an electron-donating inductive effect
find more resources at oneclass.com
find more resources at oneclass.com
Unlock document

This preview shows page 1 of the document.
Unlock all 4 pages and 3 million more documents.

Already have an account? Log in

Document Summary

Pi bond the molecule forth adjacent atoms: the sigma carbon bonded to the leaving group x, and the beta carbon adjacent to it. Alkyl halides undergo elimination reactions with bronsted-lowry bases. It is an example of beta elimination because it involves loss of elements from two. Common bases used in dehydrohalogenation: sodium hydroxide, potassium hydroxide, Elimination reaction: involves loss of elements from the starting material to form a new pi bond in the product. Dehydrohalogenation: removal of the elements of hx, one of the most common methods to introduce a pi bond and prepare and alkene. The sigma bond, formed by end-on overlap of the two sp2 hybrid orbitals, lies in the plane of. The pi bond, formed by side-by-side overlap of two 2p orbitals, lies perpendicular to the plane of the molecule. Monosubstitued alkene: has one carbon atom bonded to the carbons of the double bond.

Get access

Grade+20% off
$8 USD/m$10 USD/m
Billed $96 USD annually
Grade+
Homework Help
Study Guides
Textbook Solutions
Class Notes
Textbook Notes
Booster Class
40 Verified Answers
Class+
$8 USD/m
Billed $96 USD annually
Class+
Homework Help
Study Guides
Textbook Solutions
Class Notes
Textbook Notes
Booster Class
30 Verified Answers

Related textbook solutions

Related Documents

Related Questions