BIOL 1202 Lecture Notes - Lecture 7: Allele Frequency, Genetic Recombination, Gene Pool
7 Dec 2016
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In the population 84 plants have round seeds, and 16 have wrinkled seeds. heterozygous (rr: since each plant has 2 genes for shape there are 200 pea shape genes in the population. 120 of those shape genes are dominant (r) The frequency for the a allele is 0. 6. The frequencies for both alleles (a and a) must add up to equal 1. 0. 6 + frequency for a = 1 so the frequency for a must be 0. 4. You can also get this by the same method we got the frequency for a. Assuming that mating in the population is completely random, then the frequencies of r and r will remain constant. The chance of getting two r genes in the f1 generation is. 0. 6 x 0. 6 = 0. 36 this means 36% of the f1 generation is rr. The chance of being a heterozygous individual is. 2 (0. 6 x 0. 4) = 0. 48 this means 48% of the f1 generation is rr.
