MAC1105 Lecture Notes - Lecture 21: Intermediate Value Theorem, Synthetic Division, Polynomial

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MAC1105
College Algebra
16 Week Course
5.4 Polynomial and Rational Inequalities Notes
L. Sterling
Abstract
Provide a generalization to the terms listed in this section.
How do you [algebraically] solve a polynomial inequality?
Write the given inequality so that the polynomial expression, which is f, is being displayed
on the left side with zero being on the right side.
Find the graph’s real zeroes [if any].
Use the zeroes to divide the real number line into intervals.
Choose values between each interval and evaluate at the given values.
If fis positive, then all of the values of fin the interval will be positive.
If fis negative, then all of the values of fin the interval will be negative.
How do you [algebraically] solve a rational inequality?
Write the given inequality so that the polynomial expression, which is f, is being displayed
on the left side with zero being on the right side.
Find the graph’s real zeroes [if any].
Find the graph’s real numbers [if any].
Choose values between each interval and evaluate at the given values.
If fis positive, then all of the values of fin the interval will be positive.
If fis negative, then all of the values of fin the interval will be negative.
Remainder and Factor Theorems
(Quotient)(Divisor) + Remainder =Dividend
Division Algorithm for Polynomials
f(x)
g(x)=q(x) + r(x)
g(x)
f(x) = q(x)g(x) + r(x)
f(x) = Dividend
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Document Summary

5. 4 polynomial and rational inequalities notes: sterling. Provide a generalization to the terms listed in this section. If f is positive, then all of the values of f in the interval will be positive. If f is negative, then all of the values of f in the interval will be negative. Remainder and factor theorems (quotient)(divisor) + remainder = dividend. Division algorithm for polynomials f (x) g (x) = q (x) + r (x) g (x) f (x) = q (x) g (x) + r (x) f (x) = dividend. 1 q(x) = quotient g(x) = divisor r(x) = remainder. Since f (x) is the dividend, if f (x) is being divided by x c, which would look like f (x) x c , then the remainder would technically be f (c). First o , let f be a polynomial function.

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