18.05 Lecture Notes - Lecture 9: Mit Opencourseware
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18. 05 problem set 9, spring 2014 (iii) = 0. 1. It was spun on its edge 250 times and came up heads 140 times. Our null hypothesis was that the coin was fair and the two-sided p-value came out as 0. 066. (a) in this problem we want you to make one plot for each of (i) = 0. 5, (ii) = 0. 3, The rule-of-thumb variance for a bernoulli( ) distribution is 1/4, i. e. we use the variance for = 0. 5 no matter what the true value of is. So the rule-of-thumb variance for a binomial(n, ) is just n/4. Center your interval between the 0. 1 and 0. 9 quantiles. Suppose is the average height of a college male. You measure the heights (in inches) of twenty college men, getting data x1, . , x20, with sample mean x = 69. 55 in. and sample variance s2 = 14. 26 in2 .
