18.05 Lecture Notes - Lecture 1: Mit Opencourseware
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P (two-pair) = . 047539, p (three-of-a-kind) = 0. 021128, two pairs is more likely. We rst choose two of thirteen ranks for the two pairs. For the pair of lower rank, we choose two of four suits. For the pair of higher rank, we choose two of four suits. For the singleton card, we choose one of eleven remaining ranks: For the singleton card, we choose one of four suits. We choose one of thirteen ranks for the triple. We choose three of four suits for the triple. For the other two cards, we choose two of twelve remaining ranks. For the singleton of higher rank, we choose one of four suits: For the singleton of lower rank, we choose one of four suits: So two-pair is more than twice as likely as three-of-a-kind. You can calculate the probability of other poker hands using a similar strategy. Problem 2. (10 pts. ) answer: (reasons below) (a) p(white beats green) = 7/12.
