MTH 355 Lecture Notes - Lecture 18: Mathematical Induction

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Pch ) t p c htt iii ) conclusion by ci ) [ 2113-11=1 shows the right hand side of the equality becomes n2=it3t ten. I ) base case of n =l . Induction step becomes simply 1 we see that the statement is true in this. 3t . t gn - 1) t c 2h h ) Ii pcntt contains the right hand side of. Hn ein n2=lt3t t c 2h - d. Tkz t ( kt 172 = ( kt 1) ( kt 2) ( 21kt 1) tl. 14kt 1) since by rules the of (214-1) +6ckh )z= ( kt 1) ( kt 2) ( denominator same is the multiplication it follows. Hand side ) we only have to consider the numerator that ( kh ) ( kt 2) ( 21kt htt ( lat ( k "t. Pc htt and by i ) and ii ) and.

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