PHYS 27200 Lecture Notes - Lecture 1: Electric Field

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tealscorpion160

6 Sep 2015

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The coulomb force law unit = newton n. If f vector, multiply another r hat (unit vector of r) at the end. E = f*q (q = charge unit = coulomb c) Electric force is far larger than gravitational force . Electric field is zero at the origin of the charge (e = 0) Negative charge - converge electric field (from lecture note) Total electric field = the sum of all electric field (add up according to the components) If you have a positive charge and negative charge at the exact same position, the electric field will cancel out. ( e=0) 1>electric field at certain point due to a dipole along the x- axis. Electric field from the positive charge and the negative charge will be opposite sign because of the opposite direction that each of them are pushing or pulling.

Related Questions

a)The figure below shows a test charge q betweenthetwo positive charges. Find the force (in newtons) on thetestcharge for q = 2 ÂµC. Give a positive answer iftheforce is to the right and a negative answer if the force is totheleft.

b) For the previous question, find the electric field(innewtons/coulomb) at the position of test charge. Again, supplyapositive value if the electric field points to the right andanegative value if it points to the left.

c) How much work (in joules) is done in moving a charge of 2.5Î¼Cadistance of 53 cm along an equipotential at 10~V?

d) The field lines associated with a uniform electric fieldina region of space are shown in the figure below. Imaginedrawingtwo equipotentials in the plane of the figure, one passingthroughpoint A and and one passing through point B. If the electricfieldis 450 N/C, how much does the potential change in going from AtoB? Provide your answer in volts and use a positive value ifitincreases and a negative value if it decreases.

Please help and you will get a lifesaver rating!! Thankssomuch

I am studying for a physics exam next Monday and I need tounderstand this concept a hell of lot better than I do. Hopefullysomeone on here can dumb it down for me.

My textbook says the following:

1. If the probe charge q is positive, the electric fieldvector points in the same direction as the force on the charge; ifnegative, the electric field vector points opposite theforce.

What is this really saying? I don't understand.

2. For the equation, Electric field = K|q|/r^2 , theelectric field is going away from q if q>0, and the electricfield is going toward q if q<0.

I don't understand this either. Is the electric field going awayfrom q because the electric field is negative and q is positive,thus q is attracted to the field? If q is negative then the fieldis going to be going toward q because it's being repelled from thenegative field?

I just want tounderstand the two bolded concepts above and how they relate toeach other, if they in fact do. My job does a horrible job atexplaining it.

Thanks.

Which of the statements regarding this situation are true? Selectall that apply.

1-When one charged sphere is placed inside another the net electricfield outside the larger sphere is always larger than the field dueto the larger sphere alone.

2-If there is a positive point charge present at the center, thefield in all regions is either zero or directed away from thecenter.

3-When one charged sphere is placed inside another the net electricfield outside the larger sphere is always non-zero.

4-It is possible to have no electric field inside the outer sphereand a non-zero electric field outside the outer sphere.

5-If the outer sphere is present the electric field between itsinner radius and its outer radius (inside its solid wall, in otherwords) is always zero.

6-It is not possible to have a non-zero electric field inside theinner sphere and outside the outer sphere, but no electric fieldbetween the inner and outer spheres.

7-For a conducting sphere with a net charge Q, the electric fieldinside the sphere is zero and the electric field outside the sphereis the same as the field from a point charge of charge Q placed atthe center of the sphere.

8-As you move steadily out from the origin in this simulation theelectric field changes smoothly. The field can never jump suddenlyfrom one value to another.

9-If the outer sphere is present the way charge is distributed onthe outer sphere depends only on its charge, and not on the chargeof the point charge and the inner sphere.

PHYS 27200 Lecture Notes - Lecture 1: Electric Field

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