MATH-182 Lecture 10: MATH 182 Lecture 10: Calculus II: Integrals of sin(x)cos(x) to different powers

couse Information Elementary Linear Aget x C Ngebra question I Cheg x e Math 1B03/12cz Summe x Secure www child jonlineform 2.php?assign 5(b) 5 (b) 0/2X 5(b) 5(c) 5(c) Problem #6: Which of the following is a solution to the equation z (1 V3i (A) 21 3[cos(23T/18) i sin 23nt/18)] (B) 1/3 i Sin 8m/9)] (C 2 3[cos (10m/9) i sin( 10mt/9)] 1/3 (D) 2 cos (19m/18) i sin 19nt/18)] (E) 21 (7t/9) i sin 7m/9)] (F) 21 13 18) i Sin 13 t/18)] 1/3 1/3 (G 1/3 +isin 111t/901 (H) 2113[cos(17m/18) i sin( 17m/18) Problem #6: E Just Save Your work has been saved Back to Admin Page) Submit Problem #6 for Grading Problem #6 Attempt Attempt 2 Attempt 13 Your Answer: Your Mark: 0/2X Problem #7: Find the value of 65 V3 65 252 AM Type here to search 2017-U6-0

3. O -11 points LarsonE T5 15.6.013 Evaluate f(x, y) ds. f(x, y) = y + 4 s: r(u, v) = ui + vj + 3vk, o us!, osvs2 N eed Help?Read ItTalk to a Tuter Submit Answerl Save Progress Practice Another Version 4. 01 points | Previous Answers LarsonET5 15 6.014 Evaluate fx, y) ds f(x, y) =xy s: r(u, v)- 8 cos u i + 8 sin uj + vk 2

Find the area of the region bounded by y = sin2x and y = cos x from x = - pi / 4 to x = pi. Set up the integral and simplify. You do not need to solve. Sin 2x = cos x 2 Sin x cos x - cos x = 0 cos x (2 sin x - 1) = 0 cos x = 0 sin x = 1 / 2 pi/2, pi/6, 5 pi/6 sin 2(0) = 0 sin 2(pi / 4) = 1 cos x - sin 2x dx + sin 2x - cos x dx + finding local extrema, inflection points, intervals wh