14:440:127 Lecture Notes - Lecture 6: Parachuting, Terminal Velocity, University Of Manchester
16 Mar 2015
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440:127 spring 2015 s. j. orfanidis. Please do the following problems during your recitation session, including any additional problems given to you by your ta. Upload the complete solutions within 48hrs of the end your session: a skydiver jumps off a plane from a height of h0 meters, with an initial downward velocity v0. = 1. 2 g = 9. 81 m = 75. A = 0. 7 kg/m3, air density m/sec2, acceleration of gravity kg, skydiver"s weight (mass) skydiver"s drag coef cient m2, skydiver"s cross sectional area. + v0 vc sinh h(t) = h0 hc ln cosh. 1 v2(t) v2c a(t) = g tanh (cid:7) (cid:2) (cid:4) (cid:3) t t0 (cid:3) (cid:4) tc t t0 (cid:4) (cid:3) tc t t0 tc (cid:2) vc cosh (cid:3) g(v2 (cid:4) c v2. The quantity vc is known as the critical or terminal velocity. The skydiver can control the value of vc by changing the effective area a.
