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MATH 312 Lecture 7: CH 28.4 cont. - 09.25.18

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orangecheetah117

2 Oct 2018

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Jayme Rosenquist

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Chapter 28 determining more complicated probabilities 09/25/18. Spinner one: p(red) = , p(blue) = . Spinner two: p(red) = , p(blue) = , p(green) = . Spinner three: p(red) = 1/3, p(blue) = 1/3, p(green) = 1/3. 1/3 green: p(at least one red) = 10(1/24) + 4(1/12) = , p(no red) = 1-p(at least one red) P(no red) + p(at least one red) = 1 => 1-3/4=1/4: p(no red) = p(no red on first spin, second spin, and third spin) = p(no red on 1st) x p(no red on 2nd) x p(no red on 3rd) = x x 2/3 = 6/24 = : p(at least one blue or at least one green) = 1-p(all red) = 1-1/24 = 23/24. Of these, 65% are women and 10% of all employees have a college degree. 4,800: p(randomly selecting a female or graduate) = 3120/4800 + 480/4800 228/4800.

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