CH 104 Lecture Notes - Lecture 3: Sulfur, Transition Metal, Nitride

47 views3 pages

Document Summary

Formation of cations: nucleus of an atom has protons and neutrons, if remove an electron from an atom it becomes a cation, na- Has 11 protons, 12 neutrons, 11 electrons. 1 electron in the outer shell: 1 valence electron, na+ Has 11 protons, 12 neutrons, 10 electrons. 8 electrons in the outer shell: 8 valence electrons, elements in group 1a will want to lose an electron to become a positive cation. 2a will want to lose two electrons to make a cation. Normally in general metals want to lose electrons. Let"s say ele(cid:373)e(cid:374)t 53 iodi(cid:374)e (cid:449)ould ha(cid:448)e to lose 7 electro(cid:374)s to become krypton and become a positive cation. Extremely difficult: to become a cations must lose the electrons to have 8 valence electrons. Formation of anions: when an atom gains an electron. So it goes from positive to negative: chlorine gains an electron and becomes a negative anion.

Get access

Grade+20% off
$8 USD/m$10 USD/m
Billed $96 USD annually
Grade+
Homework Help
Study Guides
Textbook Solutions
Class Notes
Textbook Notes
Booster Class
40 Verified Answers
Class+
$8 USD/m
Billed $96 USD annually
Class+
Homework Help
Study Guides
Textbook Solutions
Class Notes
Textbook Notes
Booster Class
30 Verified Answers

Related Documents

Related Questions