CSE 241 Lecture Notes - Lecture 2: Number One Crossbar Switching System, Decimal Mark

• School: University at Buffalo
• Department: Computer Science & Engineering
• Course: CSE 241
• Professor: Ramamurthy Bina

Document Summary

Example: determine the base of the numbers such that an equation is true. (22+4) + (11+7) = (44) 44 = 44 (24)b + (17)b = (40)b (2xb + 4x1) + (1xb + 7x1) = (4xb + 0x1) 2b + 4 + b + 7 = 4b. Check (convert back to decimal and make sure that it still makes sense): x2 (b + 1)x + (2b + 2) = 0 x = (3)b x = (6)b. In base b: 6 + 3 = 11, 6 x 3 = 22. Example: converting decimal numbers to binary (1. 125)10 (1)10 = (1)2. Deal with this in two segments on either side of the decimal point. (0. 125)10 = (0. 001)2. Exa(cid:373)ple: (cid:1005)"s co(cid:373)ple(cid:373)e(cid:374)t a(cid:374)d (cid:1006)"s co(cid:373)ple(cid:373)e(cid:374)t (cid:1006)"s co(cid:373)ple(cid:373)e(cid:374)t shortcut: 11101110 (cid:1005)"s co(cid:373)ple(cid:373)e(cid:374)t (cid:894)switch (cid:1005)"s a(cid:374)d (cid:1004)"s(cid:895) (cid:1006)"s co(cid:373)ple(cid:373)e(cid:374)t (cid:894)add (cid:1005) to (cid:1005)"s co(cid:373)ple(cid:373)e(cid:374)t(cid:895) keep everything up until the first 0, then you start flipping numbers (from right to left)