PSY 207 Lecture Notes - Lecture 7: Statistical Unit
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Eight different cards would satisfy this condition, 4 (4s) or 4 (7s). Substituting these values into the equation gives the following result: p(1 or 6) = 1/6 +1/6-0 =2/6. There are four 6"s in the deck: no card has both the 4 of s and a six of any suit, p(4 of s or 6 of any suits) 1/52+4/52-0 +. 0961538. There are 13 s: one card has both a king and a s, p(a king or any ) 4/52 + 13/52 1 =-0. 67307692307. The probability of the occurrence of event a and then event b, and then event c is the product of the separate simple probabilities of those events: p(cid:894)a and b and c and . What is the probability of drawing a 4 and then a 7 from a shuffled deck of cards: we need to multiply the simple probabilities together, p(4 and 7)= p(4)*p(7) = 4/52*4/52.
