CMSC 425 Lecture Notes - Lecture 1: Collider
15 May 2018
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Problem 1.
(a) Colliders come in two different types, colliders and triggers. Think of colliders as solid physical
objects that should not overlap, whereas a trigger is an invisible barrier that sends a signal
when crossed. An example is like with the rolling ball or a character it should not pass through
a wall therefore it should be a collider. When a Character passes enters a room, there could
be trigger event that occurs when the character enters a room.
(b)
• P[0] = 1*a + 0*b + 0*c
• P[1] = ¾*a + 1/8*b + 1/8*c
• P[2] = ½*a + ¼*b + ¼*c
• P[3] = ¼*a + 3/8*b + 3/8*c
• P[4] = 0*a + ½*b + ½*c
(c) transform . Rotate (new Vector3 (0 , 45 , 0)*4)
Problem 2.
(a) U = q – p , V = c – p
(b) Lets say temp vector Y = t – p, Vector Y = ((V*U)/(U*U))*U, Therefore, t = Y + p, t =
((V*U)/(U*U))*U + p
(c) Using the equation in b to get t all you have to do is subtract it by the vector between the point t
ad t’
(d) P(t) = p(1-t) + qt, 0<= t <=1, there for we need the dist(P(t),p) <= r+s
(e) code
Problem 3.
(a) TBD
(b) TBD
Problem 4.
(a) We start with a square, and with each iteration we replace each line segment of length x by a
chain of 4 subsegments each of length (2)^1/2/4x.
Ln(4)/ln(2^(1/2)/4) = ln(4)/ ½*ln(2) - ln(4)
(b)
(i) Let d = ad δ = 9◦ . Let us assue that e start i the loer-left corner of the square
((x, y) = , ad the headig is to the east α = .
(ii) • F: Moe forard a step of legth d i the urret diretio, that is, hage the
state fro , , α to the e state +d os α, +d si α, α, ad dra a lie fro the
current position to the new position.
• +: Irease the tur agle δ, that is, hage the state fro , , α to , , α+δ.
• −: Derease the tur agle δ, that is, hage the state fro , , α to , , α−δ.
• *: “ae as −, but change the state from , , α−δ) to , , α−δ/2).
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Document Summary
Problem 1. (a) colliders come in two different types, colliders and triggers. Think of colliders as solid physical objects that should not overlap, whereas a trigger is an invisible barrier that sends a signal when crossed. An example is like with the rolling ball or a character it should not pass through a wall therefore it should be a collider. Rotate (new vector3 (0 , 45 , 0)*4) Problem 4. (a) we start with a square, and with each iteration we replace each line segment of length x by a chain of 4 subsegments each of length (2)^1/2/4x. Ln(4)/ln(2^(1/2)/4) = ln(4)/ *ln(2) - ln(4) (b) (i) (ii) Let d = (cid:1005) a(cid:374)d = 9(cid:1004) . = f + f + f + f p = {f * f + ff f +} (iii) (iv) 0 0 1 (b) t[ cd] * t[bc] * t[ab] = t[ad]
