MATH 112 Lecture Notes - Lecture 17: Even And Odd Functions, Polynomial, Coefficient

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No, the power for polynomial have to be integer. anxn+an-1xn-1++a1x1+a0 where n=0,1,2 For n degree there are at most n zeroes. Set x-ci=0, i=1,2,n. solve for x , we get zeros. For example, x2+4x+4=(x+2)(x+2), so have two same zeros(-2,0) More practice: determine a possible equation for the polynomial functions graphed below. There are three zeros: (-3,0) (1,0) (2,0). so we get a preliminary function (x+3)(x-1)(x-2), and there must a positive coefficient because it is odd function and down/up format, which is a(x+3)(x-1)(x-2) (b) Even degree, positive leading coefficient, zeros:(-10,0) (-4,0) (2,0) (6,0). so we get: a(x+10)(x+4)(x-2)(x-6) and choose a suitable coefficient a : r(x)=0. 5(x+3)(x+1)(x-2)(x-5) What is the transformation for 0. 5. it is outside , so it is vertical transformation. Even degree with positive leading coefficient up/up. So the graph looks like: (-3,0) (-1,0) (2,0) (5,0) The multiplicity is even, so it does not cross x, only touch x-axis which looks like:

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