BIO 198 Lecture Notes - Lecture 17: Restriction Enzyme, Capillary Action, Transfer Dna

14 views3 pages

Document Summary

Neu(cid:396)ospo(cid:396)a (cid:373)ake o(cid:396)de(cid:396)ed tet(cid:396)ads (cid:894)if (cid:374)o (cid:396)e(cid:272)o(cid:373)(cid:271)i(cid:374)atio(cid:374) (cid:271)et(cid:449)ee(cid:374) the (cid:272)e(cid:374)t(cid:396)o(cid:373)e(cid:396)es, the(cid:374) you"ll get all the a+ spores on the top and all a- on the bottom). If (cid:272)(cid:396)oss o(cid:448)e(cid:396) o(cid:272)(cid:272)u(cid:396)s, the(cid:374) you"ll see a(cid:374) o(cid:448)e(cid:396)lap of the chromosomes and different line up of the spores. Can calculate a map distance from the centromere to the gene. You can see that there are different ways to get recombination patterns/order that are different from the parental types. We divide tt by 2 and we divide by two also because we are counting octads here and only are spores that are recombined. You can measures the distance between the two genes as well as the distance between the centromere and gene in neurospora. There is recombination between the little b and. Distance between a and b = 5 m. u. Distance between a and c = 3 m. u.

Get access

Grade+20% off
$8 USD/m$10 USD/m
Billed $96 USD annually
Grade+
Homework Help
Study Guides
Textbook Solutions
Class Notes
Textbook Notes
Booster Class
40 Verified Answers
Class+
$8 USD/m
Billed $96 USD annually
Class+
Homework Help
Study Guides
Textbook Solutions
Class Notes
Textbook Notes
Booster Class
30 Verified Answers

Related textbook solutions

Related Documents

Related Questions