MAT 21A Lecture Notes - Lecture 7: Square Root, Asymptote
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Mat21a - lecture 7 - 2. 6: limits involving infinity part 2. To find (rational function) lim x . , divide everything by the highest power in the denominator . Same trick works for exponents which aren"t positive integers: Get rid of negative exponents: lim x . Divide by x: x x2 lim x . | 1+ 1 ( x x2 lim x . 0 1+ = 1 f (x) lim x . : same idea as lim x f (x) , but x goes to the left forever instead of right. : same as x lim x . Proving that x < m f(x) lim (x +1) x (x) f lim x . = l : in terms of an unknown (cid:304) > 0. Left inequality: this is always true, therefore we ignore it. 1 1 y because we are finding the limit as x x < m f(x) Square root both sides: x < (cid:304)