BICD 100 Lecture Notes - Lecture 13: Null Hypothesis, Genetic Counseling, Statistical Hypothesis Testing
12 Nov 2016
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1/3 chance: iii-5 has a 2/3 chance of being aa, the only possibility for having a child with the recessive trait. Then, there would be chance that their child would have the trait, so overall, x 2/3 = 1/3 chance. Clicker: imagine a genetic counselor working with a couple who have just had a child who is suffering from tay-sachs disease. Neither parent has tay-sachs, nor does anyone in their families. Because you have had one child with tay-sachs, you must each carry the allele. Any child you have has a 25% chance of having the disease. Envision a family in which the grandfather, age 47, has just been diagnosed with. Hu(cid:374)ti(cid:374)gto(cid:374)"s disease, (cid:449)hi(cid:272)h is (cid:272)aused (cid:271)(cid:455) a do(cid:373)inant allele (and the father is a heterozygote). His daughter, age 25, now has a 2-year-old son. No one else in the family has the disease.
