PHYS 1B Lecture Notes - Lecture 22: Inductor, Rl Circuit, Inductance
Document Summary
Inductance of an ideal solenoid: field produced by current i in an ideal solenoid is, b = 0n/l*i = 0ni, the magnetic flux through the solenoid due to this magnetic field is phib = ba. Inductance can be increased by increasing number of loops of wire (n) or area of loops a, or by decreasing the length of a solenoid. Clicker question: suppose 2 inductors each having inductance l were put into series. This would be equivalent to a single inductor having inductance: 2l: note that 2 solenoid inductors in series is just like having one that has 2x as many turns (2n) and twice the length (2l) Ex: what is the inductance of the pictured typical inductor, which has approximately 30 turns, a coil length of 1 cm, and a coil diameter of 0. 3 cm: l = 0n2/l * a = 10-5 h. If the current reaches its maximum value and the battery is disconnected, can apply.
