CHEM103 Lecture Notes - Lecture 4: Relative Atomic Mass, Lead, Chemical Formula

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1 mole = 6. 02 * 10^23 (avogadro"s number) 12. 011 grams of carbon = avogadro"s number of c atoms. 18. 0152 grams of water = 6. 02 * 10^23 molecules of h2o. Atomic weight of argon = 39. 948g argon = 1 mole of ar. 375 moles * (39. 948/1 mole) = 15. 0 g of ar. 50. 0 g of lead = ____ lead atoms. Atomic weight of lead = 207. 2 g pb = 1 mole pb. 50 g pb (1 mole/207. 2 g) = 0. 241 moles pb. 241 moles * (6. 02*10^23) = 1. 45 *10^23 atoms of pb. From grams to moles - divide the grams by the atomic weight. Moles to molecules - multiply moles by avogadro"s number. To go from molecules to specific atoms - multiply molecules by the number of atoms (ex: looking for 3 oxygen, multiply by 3) Percentage by mass: the mass of each element present in 100. 00 grams of a compound, expressed as a percentage.

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